find the following triangles
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Answered by
2
Answer:
YOUR ANSWER IS 92⁰
Step-by-step explanation:
SINCE AB||DE
THEREFORE angleBAC=angleCED
angleCED=35⁰
NOW,
IN∆CED...WE HAVE,
angleCED+angleEDC+angleDCE=180⁰
=>angleDCE=92⁰
Answered by
1
Answer:
AB ll DE
therefore,
angle BAE = angle AED {alternate angles}
angle AED= 35°
In ∆DCE ,
angle CED + angle CDE + angle DCE= 180° {angle sum property of triangle}
35° + 53° + angle DCE=180°
88°+angle DCE=180°
angle DCE=180°-88°
angle DCE=92°
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