find the following using the algebraic identity 1 (8 x + 3 y)²
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Answer:
=64x^2 + 9y^2 + 48xy
Step-by-step explanation:
=1(8x+3y)^2
=1×(8x)^2 + (3y)^2 + 2×8x×3y
=1×64x^2 + 9y^2 + 48xy
=64x^2 + 9y^2 + 48xy
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