Question

Find the following usong suitable identity (X+2y+4z)square

Answer 1

Answer:

(x + 2y + 4z)² = x² + 4xy + 4y² + 4z²

Step-by-step explanation:

(x + 2y + 4z)² = x² + 2y² + 4z²

x² + 2y² + 4z² = (x + 2y)² + 4z²

(x + 2y)² + 4z² = (a + b)² = a² + 2ab + b²

(x + 2y)² + 4z² = (x² + 2 × x × 2y + 2y²) + 4z²

                       = x² + 4xy + 4y² + 4z²

                 

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