Question

Find the foot of perpendicular drawn from the point (1,0,-2) to the plane 7x+3y-2z=1​

Answer 1

Step-by-step explanation:

Given a plane 2x−3y+6z+21=0

We know the formula, the distance of a point P(x

1

,y

1

,z

1

) from the plane Ax+By+Cz+D=0 is given by

A

2

+B

2

+C

2

Ax

1

+By

1

+Cz

1

+D

We need to calculate the distance from the origin P(0, 0, 0) to the place.

Distance =

2

2

+3

2

+6

2

2(0)−3(0+6(0)+21)

=

49

21

=

7

21

=3

Therefore, the length of the perpendicular drawn from the origin to the plane 2x–3y+6z+21=0 is 3.