Question

FIND THE FORCE AT T=2SEC
PHYSICS CHAPTER 4
CLASS 11​

Answer 1

Explanation:

$f = \frac{dp}{dt } \\ p = 5 {t}^{2} + 2t + 3 \\ f = \frac{d(5 {t}^{2} + 2t + 3)}{dt} \\ f = 10t + 2 \\ at \: t = 2 \\ f = 10 \times 2 + 2 = 22$