find the force between 2 point charges . 3.5mc and 10 mc kept in air at a distance of 25 cm
Answers
Answer:
The given figure shows a square of side 10 cm with four charges placed at its corners. O is the centre of the square.
Where,
(Sides) AB=BC=CD=AD=10cm
(Diagonals) AC=BD=10
2
cm
AO=OC=DO=OB=5
2
cm
A charge of amount 1μC is placed at point O.
Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O. Hence, they will cancel each other. Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O. Hence, they will also cancel each other. Therefore, net force caused by the four charges placed at the corner of the square on 1μC charge at centre O is zero.