Find the force between two charges of magnitude 4pc and 6pc which are seperated by distance of 1m.
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Answer:
Let x be the distance from charge 4μC ,
If separation between both charges is 10cm
Net potential at point x from charge 4μC is zero.
V
net
=
4πε
o
1
x
4×10
−6
+
4πε
o
1
(10−x)
−6×10
−6
0=
x
2
+
10−x
−3
2(10−x)−3x=0
x=4cm
Hence, Potential at point 4cm from charge 4μC is zero.
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