Question

Find the force exerted by the liquid on the lower surface of cylinder.

Height = 2m and radius = 2cm​

Answer 1

$\huge{\underline{\sf{\red{Answer}}}}$

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Given:

Height of Cylinder = 2 metres

Radius of cylinder = 2 centimetres

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SoluTion:

$P = P \knot + \rho gh \\ \implies 10^5 + (10)^3 (10) (2) \\ \implies 10 \times 10^4 + 2 \times 10^4 \\ \implies P = 12 \times 10^4 \\ \\ \\ \implies \huge{F=PA} \\ \implies (12\times 10^4) \times ( \pi (2)^2 ) \times 10^-4 \\ \implies \large{\boxed{\tt{ 48\pi}}}$