Question

Find the force experienced by a charge of 20 µC placed in the electric field of intensity 3.4 X 10⁷ N/C.​

Answer 1

Here the values of charge and electric field intensity are given

Charge = 20 µC

$charge = 20 \times {10}^{ - 6}$

Electric field intensity = 3.4 X 10⁷ N/C.

We have to calculate the force experienced by the charge.

Formula to calculate force experienced by a charge

Force = charge × electric field

Now, we will put the values in the formula

$force \: = 20 \times {10}^{ - 6} \times 3.4 \times {10}^{7}$

$force = 680$

Therefore, the force experienced by the charge will be 680 N