Find the force experienced by the charge 2q, shown in the figure.
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Answer:
F
2
= Force applied by q
2
on −q
1
F
3
= Force applied by (−q
3
) on −q
1
X− component of net force on −q
1
is
F
x
=F
2
+F
3
sinθ
=K
b
2
q
1
q
2
+K
a
2
q
1
q
3
sinθ
⇒F
x
=K[
b
2
q
1
q
2
+
a
2
−q
1
q
3
sinθ]
⇒F
x
=Kq
1
[
b
2
q
2
+
a
2
q
3
sinθ]
or, (
b
2
q
2
+
a
2
q
3
sinθ)
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