Question

Find the force from a pressure of 96.3 pa on an area of 7.3 m^2 ?

Answer 1

Answer:

Given :-

• A pressure of 96.3 Pa on an area of 7.3 m².

To Find :-

• What is the force.

Formula Used :-

$\clubsuit$ Pressure Formula :

$\bigstar \: \: \sf\boxed{\bold{P =\: \dfrac{F}{A}}}\: \: \: \bigstar$

where,

• P = Pressure
• F = Force
• A = Area

Solution :-

Given :

• Pressure = 96.3 Pa
• Area = 7.3 m²

According to the question by using the formula we get,

$\implies \sf\bold{P =\: \dfrac{F}{A}}$

$\implies \sf Pressure =\: \dfrac{Force}{Area}$

$\implies \sf 96.3 =\: \dfrac{Force}{7.3}$

By doing cross multiplication we get,

$\implies \sf Force =\: 96.3(7.3)$

$\implies \sf Force =\: 96.3 \times 7.3$

$\implies \sf\bold{\underline{Force =\: 702.99\: N}}$

$\therefore$ The force is 702.99 N .

Answer 2

Question :-

• Find the Force from the Pressure of 96.3 Pascal on an Area of 7.3 meter² .

Answer :-

• The Force is 702.99 Newton .

$\rule {180pt}{2pt}$

Given :-

• Pressure = 96.3 Pascal
• Area = 7.3 meter²

To Find :-

• Force = ?

Solution :-

As per the provided information in the given question, we have been given that the Pressure is 96.3 Pascal . Area is given 7.3 meter² . And, we have been asked to calculate the Force .

For calculating the Force , we will use Pressure formula :-

• $\bf {Pressure \: = \: \frac{Force}{Area}}$

But, in the question, we have been asked to calculate the Force . Therefore, by splitting the Formula, we will get :-

$\dag \: \: \bf{Force \: = \: Pressure \: \times \: Area}$

$\Longrightarrow \: \: \sf{Force \: = \: 96.3 \: \times \: 7.3}$

$\Longrightarrow \: \: \textbf {\textsf {Force \: = \: 702.99 \: N}}$

Hence :-

• Force = 702.99 Newton .

$\rule {180pt}{4pt}$

Learn More :-

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \small \bigstar \: \bf{Pressure \: = \: \large\frac{Force}{Area} } \\ \\ \\ \small \bigstar \: \bf{Area \: = \: \large\frac{Force}{Pressure} } \\ \\ \\ \small \bigstar \: \bf{Force \: = \: Area \times Pressure} \\ \\ \end{array}}\end{gathered}\end{gathered}$