Question

find the force in Newton which mass A exerts on B if B is moving towards right with 3m/s^2. also find mass of A. (all surfaces are smooth)

Answer 1

Answer:

Force is 5N and mass is 16/31 Kg.

Explanation:

Since, the force is applied at an angle then there will be its components along x and y-axis.

So, Nsin37 = 3.

Since sin37 is 3/5 so we get that N will be 5.

Since the force of same magnitude is applied on A by B hence acceleration of both A and B will be same along normal.

So, a*cos37. = 3 * sin37.

On solving we will get the value of Acceleration a to be 9/4.

So, now on applying newtons law along the vertical direction we will get.

Mg - Ncos37 = M×9/4.

M will be = 16/31 Kg.

Answer 2

Answer:

according to the question answer is given