Question

find the force of attraction between earth and 60 kg object.​

Answer 1

Answer:

m1=50 kg,m2=60 kg

d=2 m,G=6.67×10−11 Nm2/kg2

F=Gd2m1m2

=22G×50×60=750×G

=750×6.67×10−11=5.0025×10−8N

 Force of attraction by a body on earth GMm

F=(R2GMm)

G− Gravitational constant

M− Mass of earth

m− Mass of body

R− Radius of earth

hope it is helpful

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Answer 2

Answer:

Given - Mass of object(M) = 60 kg

Force = GMm/R²

Mass of earth (m) = 6×10²⁴kg

Radius of Earth (R) = 6.4×10⁶m

Gravitational constant = 6.67×10^-¹¹

$= \frac{6.67 \times10^{ - 11} \times 60 \times 6 \times {10}^{24} }{(6.4 \times 10^{6}) {}^{2} }$

$= \frac{6.67 \times {10}^{ - 11} \times 360 \times {10}^{24} }{6.4 \times 6.4 \times {10}^{12} }$

$= 586.23newton$