Question

find the force of attraction between two stones of equal masses (m)lying at a distance of 3 meter from each other on the earth's surface​

Answer 1

Answer:

$Force =  \frac{Gm^{2}}{9}$

Explanation:

According to Newton's law of Gravitation,

$F = \frac{Gm_{1} m_{2} }{r^{2} }$

Here m1 = m

m2 = m

r = 3m.

Answer 2

Explanation:

as in the newton's law of gravitation ,force = Gm¹m²/r²

So let the mass of the stones be one so G×1× 1=r²

so r²=3 so force = 3×1×1/3= 1 newton