Question

find the force of limiting friction between an iron block and horizontal surface, if coefficient of friction between block and surface is 0.08 and the mass of block is 60 kg (if g= 10 m/s^2)​

Answer 1

Answer:

48 N

Explanation:

we know that ,

f= coefficient of friction ×m×g

f=0.08×60×10

f=48 N

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Answer 2

Answer:

The force of limiting friction between the block and horizontal surface will be 48 N

Explanation:

Given data :

The coefficient of friction between the surface and block = 0.08

Mass of the block = 60 Kg

Gravitational Acceleration = 10 m/s^2

Formula to be used :

$limiting \: friction \: = coefficient \: of \: friction \: \times force \:$

Calculating Friction :

In this case, force acting on the body is the gravitational force which is given by mg, that is, mass times gravitational acceleration.

Therefore,

$friction \: = 0.08 \times mg \\ friction \: = 0.08 \times 60 \times 10 \\ friction \: = 48$

Hence, the required limiting force = 48 N

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