Question

Find the force require to stretched a wire of area of cross section 2 x 10^-4m^2 so that its length becomes 1.5 times original length. Young's modulus = 3.6 x 10^11 Nm^-2

pls answer correctly.
refer attachment for clear question..​

Answer 1

Answer:

F=10.8x10^-4

Explanation:

A=2x10^-4

dl/l=1.5

youngs modulus=Fxl/dlxA

3.6x10^11=F/1.5x2x10^-4

F=3.6x10^11x1.5x2x10^-4

F=10.8x10^7