Find the force required by a body of 9 kg which started from Rest & and attains a velocity of 10 in 2 seconds.
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Answered by
4
Thanks for the question!
Here Initial velocity = 0 m/s
Final velocity = 10 m /s.
Time = 2 s
So acceleration = 10-0/2=5 m /s²
---------------------------------------------
Force =mass*acceleration
=9*5N
=45N
Here Initial velocity = 0 m/s
Final velocity = 10 m /s.
Time = 2 s
So acceleration = 10-0/2=5 m /s²
---------------------------------------------
Force =mass*acceleration
=9*5N
=45N
Anonymous:
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Answered by
1
a=v-u/t
=10-0/2
= 10/2
= 5 m/s²
F= m*a = 9×5=45N
=10-0/2
= 10/2
= 5 m/s²
F= m*a = 9×5=45N
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