Question

Find the force required to stop
a car of mass 100 kg with two passengers each of 50 kg sitting inside if it is moving at 60 km/hr speed and takes 5s to stop

Answer 1

Answer:

666.66 Newton

Step by step explanation:

It is given that:

• Mass of car = 100 kg
• Two passengers with each of a mass of 50 kg
• Initial velocity = 60 km/h
• Car takes 5 s to stop

Force = mass*deceleration

Acceleration = (final velocity - initial velocity)/time

Initial velocity = 60 km/h = $60*\frac{1000}{60*60}=16.666\:m/s$

acceleration = (0-16.666)/5 = $-3.333\:m/s^2$

Therefore, the deceleration = $3.333\:m/s^2$

Total mass =  mass of car + 2(mass of passenger) = 100+2(50) = 200 kg

Therefore, force = 200*3.333 = 666.66 N

Answer 2

Answer:-2000/3N

Explanation. Mass_100

50 mass each person

Two persons sit inside

So total mass =100+(50+50)

= 200Kg

Velocity=60km/hr

= 60×1000÷3600

= 50/3

Force = M×a

= 200(0-50/3)÷5

=-2000/3N