find the formula for centripetal force using dimensions if it depends on mass "m",velocity "v" and radius "r" of circular path
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Centripetal Force = m^a v^b r^c
[MLT^-2] = [M]^a [LT^-1]^b [L]^c
[MLT^-2] = [M]^a [L]^(b + c) [T^-1]^b
From above
[M] = [M]^a
a = 1
[T^-2] = [T^-1]^b
-2 = -b
b = 2
[L] = [L]^(b + c)
1 = b + c
c = 1 - b
c = 1 - 2
c = -1
Substituting values of a,b and c in centripetal force formula
F = m^1 v^2 r^-1 = mv^2 / r
Formula for centripetal Force is mv^2/r
[MLT^-2] = [M]^a [LT^-1]^b [L]^c
[MLT^-2] = [M]^a [L]^(b + c) [T^-1]^b
From above
[M] = [M]^a
a = 1
[T^-2] = [T^-1]^b
-2 = -b
b = 2
[L] = [L]^(b + c)
1 = b + c
c = 1 - b
c = 1 - 2
c = -1
Substituting values of a,b and c in centripetal force formula
F = m^1 v^2 r^-1 = mv^2 / r
Formula for centripetal Force is mv^2/r
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Find the formula for centripetal force using dimensions if it depends on mass "m",velocity "v" and radius "r" of circular path
Report by Manu2072 01.08.2017
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Nakshatrapv18 · Ambitious
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JunaidMirza
JunaidMirza Physics Newton
Centripetal Force = m^a v^b r^c
[MLT^-2] = [M]^a [LT^-1]^b [L]^c
[MLT^-2] = [M]^a [L]^(b + c) [T^-1]^b
From above
[M] = [M]^a
a = 1
[T^-2] = [T^-1]^b
-2 = -b
b = 2
[L] = [L]^(b + c)
1 = b + c
c = 1 - b
c = 1 - 2
c = -1
Substituting values of a,b and c in centripetal force formula
F = m^1 v^2 r^-1 = mv^2 / r
Formula for centripetal Force is mv^2/r
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