Question

find the four angles A B C D of the parallelogram ​

Answer 1

Answer:

In triangle BCD,

5x + 3x + 2x =180°

» 10x = 180°

» x = 180/10 = 18°

therefore, angle C = 18 *5 = 90°

And angle A =90° [opposite angles are equal]

Now, angle B = 180-90 = 90° [adjacent angles are supplementary]

And angle D = 90°