Question

find the four angles of a cyclic quadrilateral ABCD in which angle A=(2y+4) , angle B=(6x-4) , angle C=(4y-4) and angle D=(7x+2)

Answer 1

✔️✔️YOUR ANSWER ✔️✔️

✌In a cyclic quadrilateral the sum of two opposite angles are always equal to 180
✌In this question,
A+D = 180...............eq. 1
B+C = 180................eq. 2

✔️SOLUTION-
Putting the value of A nd D in eq. 1
2y+4+4y-4=180
6y=180
y=30

A= 2(30)+4
=60+4
=64

B=4(30)-4
=120-4
=116

Putting the value of C and B in eq. 2
6x-4+2+7x=180
13x-2=180
13x=182
x=14

B=6(14)-4
=84-4
=80

C=7(14)+2
=98+2
=100


✌✌HOPE IT WILL HLP U