Math, asked by tsultana, 1 year ago

find the four consecutive odd number whose sum is 128

Answers

Answered by Anonymous
63
Heya ✋

Let see your answer !!!!

Let the four consecutive odd numbers be x , x + 2 , x + 4 and x + 6. Then,

according to question ,

x + x + 2 + x + 4 + x + 6 = 128

=> 4x + 12 = 128

=> 4x = 128 - 12

=> 4x = 116

=> x = 116/4

=> x = 29

1st number = 29

2nd number = 29 + 2 = 31

3rd number = 29 + 4 = 33

4th number = 29 + 6 = 35





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Answered by aman190k
19
Hey here is your answer
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Let the first odd no. be x
then, other three consecutive odd no. are
x + 2 , x + 4 , x + 6

Now , a/Q

x + x + 2 + x + 4 + x + 6 = 128
4x + 12 = 128
4x = 128 - 12
x = 116/4
x = 29

:. other three consecutive odd no. are

x + 2 = 29 + 2 = 31

x + 4 = 29 + 4 = 33

x + 6 = 29 + 6 = 35

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Hope it may helpful to you
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@ajaman. .........
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