find the four consecutive odd number whose sum is 128
Answers
Answered by
63
Heya ✋
Let see your answer !!!!
Let the four consecutive odd numbers be x , x + 2 , x + 4 and x + 6. Then,
according to question ,
x + x + 2 + x + 4 + x + 6 = 128
=> 4x + 12 = 128
=> 4x = 128 - 12
=> 4x = 116
=> x = 116/4
=> x = 29
1st number = 29
2nd number = 29 + 2 = 31
3rd number = 29 + 4 = 33
4th number = 29 + 6 = 35
Thanks :)))))
Thanks :))))
Let see your answer !!!!
Let the four consecutive odd numbers be x , x + 2 , x + 4 and x + 6. Then,
according to question ,
x + x + 2 + x + 4 + x + 6 = 128
=> 4x + 12 = 128
=> 4x = 128 - 12
=> 4x = 116
=> x = 116/4
=> x = 29
1st number = 29
2nd number = 29 + 2 = 31
3rd number = 29 + 4 = 33
4th number = 29 + 6 = 35
Thanks :)))))
Thanks :))))
Answered by
19
Hey here is your answer
______________________
Let the first odd no. be x
then, other three consecutive odd no. are
x + 2 , x + 4 , x + 6
Now , a/Q
x + x + 2 + x + 4 + x + 6 = 128
4x + 12 = 128
4x = 128 - 12
x = 116/4
x = 29
:. other three consecutive odd no. are
x + 2 = 29 + 2 = 31
x + 4 = 29 + 4 = 33
x + 6 = 29 + 6 = 35
____________________________
Hope it may helpful to you
plzzz mark me as brainlist
@ajaman. .........
______________________
Let the first odd no. be x
then, other three consecutive odd no. are
x + 2 , x + 4 , x + 6
Now , a/Q
x + x + 2 + x + 4 + x + 6 = 128
4x + 12 = 128
4x = 128 - 12
x = 116/4
x = 29
:. other three consecutive odd no. are
x + 2 = 29 + 2 = 31
x + 4 = 29 + 4 = 33
x + 6 = 29 + 6 = 35
____________________________
Hope it may helpful to you
plzzz mark me as brainlist
@ajaman. .........
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