Question

find the four consecutive odd number whose sum is 128​

Answer 1

Ok Got it:-

The First four consecutive odd numbers must be x, x+2, x+4, x+6.

so, According to Question:-

x + x+2 + x+4 + x+6 = 128

4x + 12 = 128

4x = 128 - 12

4x = 116

x= 29 Answer.

The four numbers are 29, 31, 33, 35

Hope it Helps:-

Answer 2

Answer:

29, 31 , 33, and 35 are the required four consecutive odd numbers whose sum is 128.

Step-by-step explanation:

Explanation:

Given, that the sum of four consecutive odd numbers = 128

Let x be the first odd number.

Therefore, x , (x +2), (x +4), (x + 8) are the required four consecutive odd numbers.

Step 1:

From the question sum of four consecutive odd numbers whose sum is 128.

So, we have, x , (x + 2), (x + 4) and (x +6) are the for consecutive odd numbers.

Now, from the question,

⇒ x+ (x +2) + (x+ 4) + (x+ 6) = 128

⇒4x + 12 = 128

⇒4x = 128 - 12 = 116

⇒x = $\frac{116}{4}$ = 29

Step 2:

Therefore, from step 1 we have x = 29

Now, x + 2 = 29 + 2 = 31

x + 4 = 29 + 4 = 33

and x + 6 = 29 + 6 = 35

Final answer:

Hence, 29, 31 , 33, and 35 are the required four consecutive odd numbers whose sum is 128.

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