find the four consecutive term in ap who's sum is - 54 and sum of 1st and 3rd term is - 30
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Answer:
the 4 Ap are
-18,-15,-12,-9
Step-by-step explanation:
let 4 consecutive term of the the Ap are = a-3d ,a-d ,a+d ,a+3d
according to the question=
a-3d + a-d + a+d + a+3d = -54
a+a+a+a-3d+3d-d+d= -54
4a= -54
a= -54/4
a= -13.5
next a-3d + a+d = -30
a+a -3d+d= -30
2a-2d= -30
2(a-d)= -30
a-d= -30/2
a-d = -15
-13.5-d = -15
-d = -15+13.5
- d = -1.5
d= 1.5
Ap= a-3d = -13.5- 3×1.5= -13.5-4.5 = -18
a-d = -13.5-1.5= -15
a+d = -13.5+1.5 = -12
a+3d = -13.5 +3×1.5 = -13.5+4.5 = -9
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