Question

find the four consetutive positive integer is 840.find the largest no

Answer 1

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Answer 2

if you meant sum of the 4 consecutive integers then the ans is as follows,

let the consecutive numbers be a-d, a, a+d and a+2d

ATQ, 

            a - d + a + a + d + a + 2 d = 840
                                       4 a + 2 d = 840
                                          2 a + d = 420
                                                   d = 420- 2a...............................1

then a - d = a - (420 - 2a)
                = a - 420 + 2a

            => 3a = 420
                   a = 420/3
                      = 140

thus
                     d = 420- 2*140
                        = 420 - 280
                        = 140

thus the four consecutive numbers are = a - d = 140-140 = 0
                                                                 a = 140
                                                                 a + d = 140+ 140 = 280
                                                                 a + 2d = 140+ 2*140 = 420
the largest num = 420

verification:
0 + 140 + 280 + 420 = 840