Question

Find the four digit number in which the first digit is one fourth of the last digit . The second digit is six times the first digit and the third digit is the second gig it + 3

Answer 1

Let us assume that the four-digit number be a, b, c and d. (a-b-c-d)

The first digit is one-fourth of the last digit.

The last digit is multiple of four. So, it can be 4 and 8.

Means the first digit number is one-fourth of the fourth digit.

So, the first digit number can be 1 and 2.

Also given that, second digit is six times the first digit.

b = 6a

So, the second digit number = 6(1, 2)

= 6, 12

Therefore, by looking at the second digit we can say that the first digit number is 1.

As the first digit is 1. So, the last digit number is 4. (the first digit is one-fourth of the last digit)

The above correct one is 6. As we have to tell the only one-digit number, not a two-digit number.

Also, the third digit is the second digit +3.

Means, c = b + 3

From above we have the second digit i.e. b = 3. So,

c = 6 + 3 = 9

Therefore,

Four-digit number = a-b-c-d = 1694

Answer 2

$</p><p>\huge{\tt{\pink{Hello!!! }}}$

$</p><p>\tt{\red{In \: The \: Four \: Digit \: Number \: - }}$

$\tt{\orange{let \: the \: first \: digit \: be \: x. \: }}$

$\tt{ \blue{ \therefore{the \: last \: digit \: is \: 4x \: }}}$

$\tt{ \purple{ \therefore{the \: second \: digit \: is \: 6x \: }}}$

$\tt{ \green{ \therefore{the \: third \: digit \: is \: 6x \: + \: 3. }}}$

• The Last Digit Is A Multiple of 4 i.e, 4 or 8.n

• Therefore the First Digit can be 1 or 2.

• Hence the second Digit can be 6 or 12.

• 12 is not possible therefore ; the second digit is 6.

Hence the first digit is 1.

The last digit is 4.

The third digit is 9.

$</p><p>\tt{\purple{Hence \: The \: Number \: Is \: 1694 . }}$