Question

find the four numbers in AP whose sum is 6 and product of whose extremes is 10 times the product of the two intermediate terms

Answer 1

ur required ap is

3/2, 6, 21/2 ,15

assumed no . are

a+3d, a+d, a-d, a-3d

Answer 2

☺here is s your answer☺

if four terms ar in ap- so, a+3d+a+d+a-d+a-3d=6

so, a = 3/2
now , according to qus.-



10(a+d)(a-d) = (a+3d(a-3d)

10a²-10d² = a²- 9d²

so, we can say - 3a = d
but above ,, a= 3/2
so, d= 9/2
hence, a+3d = 15
a-3d = -12
a-d = -3
a+d = 6

⭐☺⭐hope it helps u⭐☺⭐