find the Fourier Series of x in 0<x<a
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Answer:
f(x)=a02+∞∑n=1dnsin(nx+φn)orf(x)=a02+∞ ∑n=1dncos(nx+θn). Fourier Series of Even and Odd Function
Step-by-step explanation:
Find the Fourier series for the square
2
π
-periodic wave defined on the interval
[
−
π
,
π
]
:
f
(
x
)
=
{
0
,
if
−
π
≤
x
≤
0
1
,
if
0
<
x
≤
π
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