Math, asked by aryantyagi18, 5 months ago

Find the Fourier sine and cosine series of the

function () = {x, 0 < < 2

2, 2 ≤ < 4}​

Answers

Answered by Anonymous
0

Answer:

sn=36=2n \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\ [a+an]36=2n[1+11]3 \div  \div  \div  \div (())))) { { { { { { { { { { { { { { { { { { { { { { { {?}^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} 6=n∗6thereforen=6sotheno.termsARE6hopeitwillhelpyouthankyou.</p><p>

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