Question

Find the fourth proportional of the following quantities. 3/2, 7/3, 13/4 kg​

Answer 1

Answer:

Here is your answer buddy,

Let X be the required fourth proportion.

Then, we have

3/2:7/3::13/4:X

Here, means = 3/2:X and extremes = 7/3:13/4

now, product of means = product of extremes

$\frac{3}{2} \times x = \frac{7}{3} \times \frac{13}{4} \\ = > x = \frac{7}{3} \times \frac{13}{4} \times \frac{2}{3} \\ = > x = \frac{91}{18}$

.°. The require fourth proportion = 91/18