Question

find the fourth proportional to x^3-y^3 ,x^4+y^4+x^2*y^2 and (x-y)

Answer 1

Answer:

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ok

Answer 2

Answer:

x2+y2-xy

Step-by-step explanation:

Let A be the fourth proportional then

x3-y3:x4+x2y2+y4=x-y:A

→x3-y3/x4+x2y2+y4(x-y)/A

→A(x3-y3)=(x-y)(x4+x2y2+y4

→A=(x-y)(x4+x2y2+y4)/x3-y3

→A=(x-y)(x2+y2+xy)(x2+y2-xy)/(x-y)(x2+xy+y2)

→A=x2+y2-xy)