find the fourth root of 89-28√10
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(√5-√2)
Step-by-step explanation:
89-28√10
89-2x19√10
89-2x√19²x√16
89-2x√1960
89 - 28sqrt(10); 8y - 2 * 19 * sqrt(10); 89 - 2sqrt(19 ^ 2) * sqrt(10); 8g - 2sqrt(1960); 99+90-2* sqrt 99* sqrt 90; ( sqrt 49 - sqrt 70 ). ²( 7- sqrt 90 )^ 2; (7 - 2sqrt(10)) ^ 2; (2 + 5 - 2sqrt(2) * sqrt(5)) ^ 2; (sqrt(2) - sqrt(5)); =2( sqrt 5- sqrt 2 )^ 4 or (sqrt(5) - sqrt(2)) ^ (2 * 2)
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