Question

Find the fourth term from the end in an A.P. -11, -8, -5, . . . , 49. Solve the word problem

Answer 1

Answer:

40

Step-by-step explanation:

As per the question,

We have been provided the series which are in A.P

-11, -8, -5, . . . , 49

Now,

First term, a = -11

Common difference, d = -8 - (-11) = 3

Last term = 49

Formula for nth term of A.P is given by:

$T_{n} = a+(n-1)d$

Let the last term be = n

Therefore,

$T_{n} = -11+(n-1)(3)$

$49 = -11+(n-1)(3)$

49 + 11 = 3(n-1)

n = 21

That is total number of terms = 21

Now the fourth term from the end = 18th term from the beginning

Therefore,

$T_{n} = -11+(n-1)(3)$

$T_{18} = -11+(18-1)(3)$

$T_{18} = 40$

Hence, the value of fourth term from end = 40