Question

Find the fourth term of an A.P 4,9,14..
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Answer 1

Answer:

t1 = 4

t2 = 9

t3 = 14

d = t2-t1 = 9-4 =5

t4 = t3 + d

t4 = 14 + 5

t4 = 19

Answer 2

SOLUTION

TO DETERMINE

The fourth term of an A.P 4 , 9 , 14 . . . .

CONCEPT TO BE IMPLEMENTED

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

EVALUATION

Here the given arithmetic progression is

4 , 9 , 14 . . . .

First term = a = 4

Common Difference = d = 9 - 4 = 5

Hence the required fourth term

= a₄

= a + 3d

= 4 + ( 3 × 5 )

= 4 + 15

= 19

Fourth can be calculated as below

The required fourth term

= Third term + Common Difference

= 14 + 5

= 19

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