Question

Find the fraction which becomes 1/2 when its numerator is increased by 6 and is equal to 1/3 when its denominator is increased by 7

Answer 1

Answer:

Let the initial fraction is x/y

If we increase numerator by 7 then the fraction becomes 1/2(given)

=>x+6/y=1/2

=>2x+12=y (equation 1)

If we increase denominator by7 then the fraction becomes 1/3(given)

=>x/y+7=1/3

=>3x=y+7

=>y=3x-7 (equation 2)

From eqn 1 and 2

2x+12=3x-7

=>x=5

Substitute x=5 in eq 1 we get value of y

2x+12=y

10+12=y

Y=22

Therefore the fraction is 5/22

Answer 2

Answer:

Step-by-step explanation:

Let numerator be x

And denominator be y

According to question.

X+6/y =1/2

Cross multi the eq

It become ....... 2x +12= y......eq 1

X/ y+7 =1/3

It become ........y+7 = 3x.......eq 2

Y= 2x+12 we will substitute the value of y in eq 2

2x+12+7= 3x

19+2x = 3x

19= 3x-2x

19=x

Now we put x= 19 in

Y=2x + 12

Y = 2× 19 +12

Y= 38 +12

Y= 50

So the fraction is 19/ 50

Hope it's help u ...