Find the fraction which becomes to 2/3 when the numerator is increased by 2 and equal to 4/7 when the denominator is increased by 4.
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let the fraction be x/y.
According to question,
x/y+2 =2/3 -----------(1)
Again,
x/y+4 =4/7-------------(2)
Solving eq. (1)
x/y+2=2/3-------(1)
3x=2y+4 {By cross multiply}
3x-2y=4-----------(3)
Solving eq.(2)
x/y+4=4/7---------(2)
7x=4y+16 {By cross multiply}
7x-4y=16--------------(4)
Now, Solving eq.(3)&(4)
3x-2y=4----------×7
7x-4y=16--------×3
so, the eq.(3)&(4) will now be
21x-14y=28-------(5)
21x-12y=48-------(6)
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shigufta:
by changing signs we can get the value of x and then we put the value of x in the eq 3 to get the value of y
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