find the free fall accleration of an object on the surface of the moon,if the radious of the moon and its mass are 1740km and 7.4×10²²kg respectively. Compare the value with free fall accleration of a body on thesurface of earth.
(ans; 1.63 m/s²) you try your level best
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We know that g = GM/r^2
= (6.673 * 10^-11 N.m^2/kg^2) * (7.4 * 10^22 kg)/(1740000 m)^2
= 1.63m/s^2
Hope this helps!
= (6.673 * 10^-11 N.m^2/kg^2) * (7.4 * 10^22 kg)/(1740000 m)^2
= 1.63m/s^2
Hope this helps!
ehbdhjxhknh:
can we use the constant value of G in each problem
Yes.
or is it meant for only this problem
U can use with that formula.
There are 2 constant values g = 9.8 m/s^2 and G = 6.673 x 10-11 Nm^2/kg^2
Those values never change.
you mean 6.673×10^-11
Yes.
thanks
Welcome
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