Chemistry, asked by sartajmanower8681, 1 year ago

Find the freezing point of a solution containing 0.520 gram glucose dissolved in 80.2 gram of water

Answers

Answered by jomintocon

1

ΔTb=Kb×m

=Kb×WBMB×1000WA

ΔTb=0.52×0.52180×100080.2

=270.414436=0.0187

∴ Boiling Point = 373 + 0.0187 = 373.0187 K

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