Question

Find the freezing point of a solution containing 2 grams of naphthalene (C10H8) in 50 grams of benzene, , and its kriscopic constant is 5.2?

Answer 1

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Answer 2

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Depression in the freezing point =ΔTf=5.45−3.55=1.9oC

Molar mass of C2H2Cl4=12×2+2×1+4×(35.5)=168 g/mol

The number of moles is the ratio of mass to molecular weight.

Number of moles of solute =1687.24=0.0431

The molality of solution is the number of moles of solute in 1000 g of water.

Molality =115.30.0431×1000=0.374

Depression in the freezing point :

ΔTf=Kbm⟹1.9=Kb×0.374 

Kb=5.08oC/m