Question

Find the frequency of heterozygotes in a population of frogs ina pond , where 4 percent of the population shows recessive phenotype

Answer 1

Answer:

4 percent of the population shows a recessive phenotype is 0.32

Explanation:

As per the data given in the question,

We need to find the frequency of heterozygotes in a population of frogs in a pond.

As per the question,

It is given that,

The frequency of heterozygous is given by 2pq.

where

p=Frequency of dominant.

q=frequency of recessive.

As we know,

heterozygotes is a living entity with two different versions of a certain gene, the offspring of which may differ in a specific trait.

So, from the data given in the question, we have a value of p=0.80

and q=0.2.

Now for finding the value of the frequency, we will put the value of p and q in the above formula.

Thus, we will get it like this:

Frequency =$2pq=2 \times (0.80) \times (0.20) =0.32\:Hz.$

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