Question

Find the frequency of heterozygotes in a population of frogs in a pond, where 4 percent of the
population shows recessive phenotype.​

Answer 1

Explanation:

p2 + 2pq + q2 = 1 and p + q = 1

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p2 = percentage of homozygous dominant individuals

q2 = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Answer 2

Explanation:

• p is the frequency of the "A" allele (dominant) q is the frequency of the "a" allele (recessive) In the equation, p2 represents the frequency of the homozygous GENOTYPE (AA), q2 represents the frequency of the homozygous genotype (aa), and 2pq represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.
• so given is q2 = 0.04, q = 0.2
• p+q=1 therfore p= 0.8
• 2pq = 0.32