Question

find the g.c.d of (x+3) (x2+5x-4) & (2x2+7x+3) (x+3)​

Answer 1

Answer:

g.c.d of (x+3) (x2+5x-4) & (2x2+7x+3) (x+3)​  is  (x+3)

Step-by-step explanation:

Given numbers are ,

$[(x+3)(x^{2} +5x-4)]$ $and$  $[(2x^{2} +7x+3)(x+3)]$

Let, $A=$$[(x+3)(x^{2} +5x-4)]$

        $=(x+3)*(x^{2} +5x-4)$

and, $B=[(2x^{2} +7x+3)(x+3)]$

         $=(x+3)*(x+3)*(2x+1)$

∴ Then, g.c.d of $[(x+3)(x^{2} +5x-4)]$  and $[(2x^{2} +7x+3)(x+3)]$ is  (x+3)