Question

Find the G.P whose third term is 9/4 and
whose sixth term is 243/32​

Answer 1

Step-by-step explanation:

Let GP's third term be 9/4 and sixth term be 243/32

Let increment=x

9/4+3x=243/32

3x=243/32-9/4

x=(243-72)/(32*3)=171/(32*3)=57/32.

So GP starts with first term=9/4-2x=9/4-57/16=-21/16

Second term=-21/16+57/32=15/32

So, GP is {-21/16,15/32,9/4.........)

Answer 2

Answer:

please refer to the attachment for your answer

hope it helps