find the gauge pressure and absolute pressure in N/m^2 at a point 4 m below the free surface of a liquid of specific gravity 1.2 , if the atmospheric pressure is equivalent to 750mm of mercury ?
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Absolute pressure = gauge pressure + atmospheric pressure.
"Gauge Pressure" is the pressure due the liquid alone. This is given by:
GP
=
ρ
g
h
=
10
3
×
9.8
×
12
=
1.17
×
10
5
N
.
m
−
2
=
117
kPa
To get the absolute pressure we need to add on the pressure due to the weight of the air above it. We add on the atmospheric pressure which I will assume to be
100
kPa
Absolute pressure
=
117
+
100
=
217
kPa
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