Math, asked by lalpekhluii7, 5 months ago

find the gcd of 14a²b⁵ and 21a³b²c(with solutions)

Answers

Answered by bushrakhan406

14

Answer:

14a²b⁵ = 2*7*a²b⁵

21a³b²c = 3*7*a³b²c

gcd= 7a²b²

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