Math, asked by Taetae4, 1 month ago

find the gcd of the polynomial (x2-1), (x²+3x+2) and (x2+7x+6)​

Answers

Answered by Gurshaan99
4

Answer:

x2−3x+2=x2−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x2−4x+3=x2−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

Option A

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