find the gcd of x^3-x^2-4x-6 and x^2-2x-3
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Let f (x) = x3 – x2 – 4x – 6 = (x – 3) (x2 + 2x + 2)
and g (x) = x2 – 2x – 3 = (x + 1) (x – 3)
Hence GCD of f (x) and g (x) is (x – 3)
and g (x) = x2 – 2x – 3 = (x + 1) (x – 3)
Hence GCD of f (x) and g (x) is (x – 3)
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