Question

find the general equation of cosecx+cotx= 1/√2 solve this.
please​

Answer 1

Answer:

<br>

rArr cot x= (-1)/(sqrt(3))

<br>

rArrtanx=-sqrt(3)=-"tan"(pi)/(3)=tan(pi-(pi)/(3))="tan"(2pi)/(3)

<br>

rArrtanx= " tan "(2pi)/(3)

<br>

rArrx=(npi+(2pi)/(3))

, where

ninI

. <br> Hence , the general solution is x

(npi+(2pi)/(3))

, where

ninI

. <br> (ii)

"cosec "x+sqrt(2)=0

<br>

rArrsinx-(1)/(sqrt(2))=-"sin "(pi)/(4)=sin(pi+(pi)/(4))="sin"(5pi)/(4)

<br>

rArrsinx="sin"(5pi)/(4)

<br>

rArrx={npi+(-1)^(n)*(5pi)/(4)