Question

find the general solution for tan3x=cotx
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Answer 1

Step-by-step explanation:

$tan3x = cotx \\ tan3x =tan( \frac{\pi}{2} - x) \\ 3x = n\pi + \frac{\pi}{2} - x \: \:, \: n\pi - \frac{\pi}{2} + x \\ 4x = n\pi + \frac{\pi}{2} \:, \: \: 2x = n\pi - \frac{\pi}{2} \\ x = \frac{n\pi}{4} + \frac{\pi}{8} \: , \: x = \frac{n\pi}{2} - \frac{\pi}{4} \\ \\ hope \: it \: will \: help \: you \:$

Answer 2

Answer:

theta = 1/4 (nπ+π/2) = π/4 (n+1/2)

Step-by-step explanation:

given equation can be written as

tan 3x=tan (π/2-0)

here the principal value, α=π/2-0

the most general solution is, therefore, 3x=nπ+α

I. e., 3x=nπ+π/2-0 or 4x=nπ+π/2

>x=1/4 (nπ+π/2)=π/4(n+1/2),where n€z

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