Question

Find the general solution for the equation 2 sinx + (√3)cosx = 1 + sinx

Answer 1

Answer:

2sinx + 3–√3cosx = 1+ sinx

Or sinx + 3–√3cosx = 1

1−3–√cosx = sinx Squaring both sides ,we have1+3cos2x −23–√cosx = sin2x Or 1+3cos2x −23–√cosx = 1− cos2xOr 4cos2x −23–√cosx = 02cosx(2cosx −3–√) = 0Or cosx = 0  , so x = (2n+1)π2 , n = 0 ,1..And (2cosx −3–√) = 0Or cosx =3√2Or x = 2nπ ±π6

Step-by-step explanation:

Answer 2

Answer:

answer is in attachment see attachment